A difficult binary operation for me:(

[memethemyn]

Hi..

In a project I use 9 of Emotron VFX drives. But in modbus the emotron uses its own procedure like EInt.

That I want to read input registers I must take an 16 bit data and the value I need the first 11 bit and then convert it to decimal again..

For example I take a data as 61563

it is 1111000001111011

the blue bits its my real value.. when I convert the blue bits to decimal I took 123 the value what I want..

How can I do this

Help please..

[Patrick Hall]

I may be mistaken, but I think what you want is something like this..

ModbusTag_BitMapped.png (10.94 KiB) Viewed 6807 times

If your Emotron drive were actually using Modbus Register 40000 for your 61563 value, then by mapping a tag to 40000.0-10 (default controller register size is INT16 but you can change it to UINT16 if you prefer un-signed behavior). The result is that the Value of Tag1 is driven by just the 11 bits specified by the ".0-10" portion. If you were to write a value from the HMI back to this tag (assuming read/write) then the value written would be masked by the bits specified as well.

[memethemyn]

A question again:(

I tried to solve the problem as you described but I want a little cheat..

I planned to masking the bits and I wrote a sample code as you see below:

Code: Select all

			int deger1; 
			int deger2;
			int deger3;
			 
			deger1 = (Globals.Tags.deger1.Value);
			deger2 = (Globals.Tags.deger2.Value);
			deger3 = deger1&deger2;
			

but these codes didnt give me a result.

Where is the wrong

[mark.monroe]

Maybe this post will help.

If you are using & both numbers will have to have a 1 in them for it to stay a one.

1111 1000 & 0011 1111 = 0011 1000

Are you sure your mask is correct? You may want to use uints so that you do not have to deal with the sign bit.